By Jacob Kogan PhD (auth.)

ISBN-10: 3540199195

ISBN-13: 9783540199199

ISBN-10: 3540393587

ISBN-13: 9783540393580

A primary challenge up to the mark conception is anxious with the steadiness of a given linear procedure. The layout of a regulate procedure is mostly in keeping with a simplified version. the genuine values of the actual parameters could range from the assumed values.
Robust balance and Convexity addresses balance difficulties for linear structures with parametric uncertainty. the applying of convexity innovations results in new computationally tractable balance standards for households of attribute features with nonlinear dependence at the parameters. balance effects in addition to balance standards for time-delay structures with uncertainties in coefficients and delays are reported.

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Extra resources for Robust Stability and Convexity

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A o + jbO)sThe values of the nominal polynomial on the boundary of the stability region p(6(w), 0) are denoted by U(w) + j V ( w ) . First we consider the Schur stability case. 1 l¢~ stability radius of complex Schur polynomials . The stability region ~2 is the open unit disc, and the parameterization of the boundary is given by 6(w) = e3w, 0 < w < 27r. 4). 3) is given by the formula [(1,d~,,d~,... , ci-~),(u(,~) + j v(~)) 50 So the coordinates ¢i + j'@, i = 0 , . . , mv], -~,~[u(~) c o s , ~ + v ( ~ ) si~ ~ ] ) .

17) are Hurwitz stable. Proof: Suppose that there exists an unstable polynomial p(s) E P. ,. T h e condition 0 ~ 790 leads to the existence of 0 < w < w' so that 0 • 079~. Let e • E, and o • O be such that The boundary of the value set 079w is maid up of four segments 4-Ap(jw, v ~+I) =i=(1 - A)p(jw, v°+t), 0 < ,~ < 1. Due to the assumptions of the theorem the segments do not contain the origin. This contradiction completes the proof. 8. E x t r e m e P o i n t R e s u l t s In this section we consider a convex stability region ft.

K a h a n Theorem [Kah], or M a r t i n [M]). 4 be a nonsingular n x n matrix. Given an n x ra m a t r i x B, an m x k m a t r i x D, and a k x n m a t r i x C if Ilk; CA-1B, mII= 0. [Ilk; CA-1B, m][] -1 otherwise. min{llm; D, k[l , A + B D C is singular} = [ oe ( Proof: First consider the case when Ilk; CA-1B, ml] = o. We show that in this case the m a t r i x ~4 + B D C is always nonsingular. , there exist a m a t r i x D, and x ¢ 0 such t h a t (,4 + B D C ) x = 0, t h a t is A x = - ( B D C ) x , and 0 ¢ x = - A - I ( B D C ) x .

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Robust Stability and Convexity by Jacob Kogan PhD (auth.)


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